In his second item analysis, Teacher Luis found out that more from the lower group got the test item #10 correctly. This means that the test item _.
A. has a negative discriminating power
B. has a lower validity
C. has a positive discriminating power
D. has a high reliability
A. because negative discrimination means that more students from the lower group got an item correctly.
This is the first step in planning an achievement test.
A. Select the type of test items to use.
B. Decide on the length of the test.
C. Define the instructional objective.
D. Build a table of specification.
C. because the first step in planning an achievement test is to formulate the instructional objectives.
Which is true about normal distribution?
A. The mean, the median, and the mode are equal.
B. Most of the scores are high
C. The mode is high.
D. Most of the scores are low.
A. One of the characteristics of normal distribution is that the mean, median, and mode are equal.
Most of the students who took the examination got scores above the mean. What is the graphical representation of the score distribution?
A. normal curve
B. mesokurtic
C. positively skewed
D. negatively skewed
Option D, because a negatively skewed distribution means that students perform well in the said examination or the scores of the students concentrated on the right part of the curve.
Which statement best describes a negatively skewed score distribution?
A. Most examinees got scores above the mean.
B. The value of median and mode are equal.
C. The value of mode corresponds to a low score.
D. The value of median is higher than the value of mode.
Option A, because a negatively skewed distribution describes a good performance of the students. The students performed well because most of the examinees got scores above the mean.
Which objective below is at the highest level in Bloom’s taxonomy?
A. Explain how trees receive nutrients
B. Explain how a tree functions in relation to the ecosystem
C. Rate three different methods of controlling tree growth
D. List the parts of a tree
Option C, because rating three different methods of controlling tree growth deals with the highest level of Bloom’s taxonomy, which is evaluation. Option A and option B deals with comprehension, while option D deals with knowledge.
This is a type of statistics that draws conclusions about the sample being studied.
A. Inferential and co-relational
B. Inferential
C. Descriptive
D. Co relational
Option B, because Inferential Statistics is concerned with the formulation for inferences of conclusions about a population based on the sample that is drawn from the population.
About how many percent of the cases fall between -2SD and +2SD in the normal curve?
A. 95.44
B. 68.26
C. 99.72
D. 99.85
Option A, because the area of the normal curve from -2SD to + 2SD is approximately 95.44%. To illustrate from mean to -1SD is also 34.13%. from mean to -1SD is also 13.59%. From 1SD to 2SD is 13.59%; from -1SD to +1SD is 13.59%. Thus, the area under the normal curve is 34.13% + 34.13% + 13.59% + 13.59% = 95.44%.
Which error do teachers commit when they tend to overrate the achievement of students identified by aptitude tests as gifted because they expect achievement and giftedness to go together?
A. Generosity error
B. Central tendency error
C. Severity error
D. Logical error
Option A, because if a teacher gives additional grade to the students who performed well in the class or in the examination, then he commits a generosity error.
Florante’s scores in Mathematics quizzes are as follows: 90, 85, 70, 65, 99, 78. What is the mean of these scores?
A. 65
B. 99
C. 85.5
D. 81.17
Option D. To compute for the mean get the sum of all the scores is 487, divide it by 6, to arrive at 81.17.
