Assessment of Learning Part 9 - LET REVIEWER 2023

PROFESSIONAL EDUCATION BASED ON THE NEW CURRICULUM ASSESSMENT OF LEARNING Assessment of Learning Part 9

Item 15	A	B	C	D
Upper 27%	3	6	5	1
Lower 27%	6	4	2	3

Question 1

What should Ms. Agustin do with item number 15?
A. Reject
B. Retain
C. Revise
D. Make it bonus item

Answer

C. Item 15 should be revised. It is within the acceptable level of difficulty that is 33% but with low discriminating power that is 13% only.

Batch	Number of Test Takers	Average
I	10	88
II	25	95
III	15	86
IV	10	98

Question 2

University X conducted scholarship examination to Four batches of test takers. The table below shows the performance of each batch.
What is the overall average of the test takers?
A. 91.00
B. 91.75
C. 92.00
D. 92.08

Answer

D. 92.08. Overall average = (10(85) + (25(95) + (15(86) + (10(98)]/60 = 5525/60 = 92.08

Question 3

What type of error was committed by a researcher if he commits a type l error?
A. Rejecting the null hypothesis which is true
B. Accepting the null hypothesis which is false
C. Generosity error
D. Severity error

Answer

A. Type l error means, rejecting the null hypothesis which is true. Meanwhile, type 11 error means accepting the null hypothesis that is false.

Question 4

Most of the students got scores above the mean in an achievement test conducted by DepEd. What does this mean?
A. Positively skewed
B. Negatively skewed
C. Normally distributed
D. Mean is equal to median

Answer

B. Negatively skewed distribution means that there are more students who got scores above the mean value. Negatively skewed is also known as skewed to the left.

Subject	Emil’s score (x)	Mean score	Standard deviation (5)
Math	88	86	1.5
English	90	88	2.0
Music	92	91	1.1

Question 5

In which subject/s did Emil perform most poorly?
A. Math and English
B. Math
C. English
D. Music

Answer

D. Emil performed most poorly in Music because the z = 0.91. The z score of math = 1.33, the z score of English = 1.00. The smaller the value of z, the poorer the performance is. Meanwhile, the larger the value of z, the better the performance.

Subject	Emil’s score (x)	Mean score	Standard deviation (5)
Math	88	86	1.5
English	90	88	2.0
Music	92	91	1.1

Question 6

What type of learners is Emil?
A. Musical
B. Logical
C. Linguistic
D. Interpersonal

Answer

B. The best performance of Emil is in Mathematics. Hence, he is a logical type of learner.

Subject	Emil’s score (x)	Mean score	Standard deviation (5)
Math	88	86	1.5
English	90	88	2.0
Music	92	91	1.1

Question 7

Which group of scores is most spread?
A. Math and Music
B. Math
C. Music
D. English

Answer

D. English scores is the most spread because the CV = 2.27% which is higher than CV of Math and Music. The computed CV = (standard deviation / mean) x 100% as follows: CV math = 1.74%, CV English = 2.27%, CV Music = 1.21%

Subject	Emil’s score (x)	Mean score	Standard deviation (5)
Math	88	86	1.5
English	90	88	2.0
Music	92	91	1.1

Question 8

Which group of scores is less spread?
A. Math and Music
B. Math
C. Music
D. English

Answer

C. Music has the lowest CV = 1.21%. Hence, the scores in Music are the less spread among the 3 subjects.

Subject	Emil’s score (x)	Mean score	Standard deviation (5)
Math	88	86	1.5
English	90	88	2.0
Music	92	91	1.1

Question 9

The computed value of r the scores in Mathematics and English is 0.85. What does this mean?
A. Math score is related to English score.
B. The higher the score in Mathematics, the higher the score in English.
C. The higher the score in Mathematics, the lower the score in English.
D. Math score is not anyway related to English score.

Answer

B. r = 0.85 means that, the higher the score in Mathematics, the higher the score in English. (High positive Correlation)

Question 10

Which graph describes the relationship that exists between two sets of data?
A. Pictograph
B. Frequency polygon
C. Histogram
D. Scatter gram

Answer

D. Scatter gram is the most appropriate to describe the relationship between the two variables.

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